[PLUG] Re: [PJUG Javamail] Re-resolved: OT: Formula For Determining # Of Digits . . .

[Prashant Kumar]

Speaking of efficieny, how efficient is Math.log10() ? How about 

x = the number itself
int count = 0;
while (x >= 1) {
 x = x/10;
 count++;
}
return count;




On Fri, 2005-02-18 at 11:27, Robb Shecter wrote:
> Jon LeVitre said:
> > It will depend on the distribution or your data, but if the data is
> > random, Travis's method will be more efficient.
> 
> Ok, if we're going to really get geeky here,  :-) let's consider space as
> well as time efficiency:
> 
> Another problem with the easy string-based solution could be object
> creation.  The OP's original problem mentioned a number like '032', so it
> sounds like it's a string.  So the operation would be;
> 
>    String -> Integer -> String -> Compute length
> 
> Two new objects would be created per execution.
> 
> By the way, JDK 1.5 has a new method, Math.log10() ... which doesn't
> suffer from the rounding error.
> 
> Robb
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